![Hiroaki Nishikawa on Twitter: "What is fascinating about active-flux hyperbolic-diffusion schemes is that one can discretize the advection term as a source term. Here is the slides used some years ago https://t.co/be4LYwkSTE Hiroaki Nishikawa on Twitter: "What is fascinating about active-flux hyperbolic-diffusion schemes is that one can discretize the advection term as a source term. Here is the slides used some years ago https://t.co/be4LYwkSTE](https://pbs.twimg.com/media/D9hQRF_XkAAC1VP.jpg)
Hiroaki Nishikawa on Twitter: "What is fascinating about active-flux hyperbolic-diffusion schemes is that one can discretize the advection term as a source term. Here is the slides used some years ago https://t.co/be4LYwkSTE
![Passive diffusion and mass flux. Passive diffusion is the only driving... | Download Scientific Diagram Passive diffusion and mass flux. Passive diffusion is the only driving... | Download Scientific Diagram](https://www.researchgate.net/publication/256490245/figure/fig4/AS:340907195944965@1458290017848/Passive-diffusion-and-mass-flux-Passive-diffusion-is-the-only-driving-force-of-dialysis.png)
Passive diffusion and mass flux. Passive diffusion is the only driving... | Download Scientific Diagram
![Flux equations for gas diffusion in porous media | International Groundwater Resources Assessment Centre Flux equations for gas diffusion in porous media | International Groundwater Resources Assessment Centre](https://www.un-igrac.org/sites/default/files/2021-10/Screenshot%202021-10-04%20at%2015.53.21.png)
Flux equations for gas diffusion in porous media | International Groundwater Resources Assessment Centre
The definition of self-diffusion flux using the net flux of molecules... | Download Scientific Diagram
![SOLVED: Solve the diffusion equation with the no-flux boundary conditions: ∂C/∂t = D ∂²C/∂z² C(z,t)|z=0 = C(z,t)|z=L = 0 C(z,t=0) = Co(z) Here D is the diffusion coefficient, L > 0 is SOLVED: Solve the diffusion equation with the no-flux boundary conditions: ∂C/∂t = D ∂²C/∂z² C(z,t)|z=0 = C(z,t)|z=L = 0 C(z,t=0) = Co(z) Here D is the diffusion coefficient, L > 0 is](https://cdn.numerade.com/ask_images/492e505361c5484693d897e4fab2f548.jpg)
SOLVED: Solve the diffusion equation with the no-flux boundary conditions: ∂C/∂t = D ∂²C/∂z² C(z,t)|z=0 = C(z,t)|z=L = 0 C(z,t=0) = Co(z) Here D is the diffusion coefficient, L > 0 is
![physical chemistry - Why does the factor of ⅔ come in when we calculate net flux due to diffusion for an ideal gas - Chemistry Stack Exchange physical chemistry - Why does the factor of ⅔ come in when we calculate net flux due to diffusion for an ideal gas - Chemistry Stack Exchange](https://i.stack.imgur.com/PbSUA.jpg)